Base | Representation |
---|---|
bin | 10000011101100… |
… | …10101110110001 |
3 | 100121211222110112 |
4 | 20032302232301 |
5 | 240323024122 |
6 | 21411511105 |
7 | 3264535616 |
oct | 1016625661 |
9 | 317758415 |
10 | 138095537 |
11 | 70a51248 |
12 | 3a2b8495 |
13 | 227c1548 |
14 | 144aa50d |
15 | c1cc2e2 |
hex | 83b2bb1 |
138095537 has 2 divisors, whose sum is σ = 138095538. Its totient is φ = 138095536.
The previous prime is 138095533. The next prime is 138095543. The reversal of 138095537 is 735590831.
It is a happy number.
138095537 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 125978176 + 12117361 = 11224^2 + 3481^2 .
It is a cyclic number.
It is not a de Polignac number, because 138095537 - 22 = 138095533 is a prime.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 138095494 and 138095503.
It is not a weakly prime, because it can be changed into another prime (138095533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69047768 + 69047769.
It is an arithmetic number, because the mean of its divisors is an integer number (69047769).
Almost surely, 2138095537 is an apocalyptic number.
It is an amenable number.
138095537 is a deficient number, since it is larger than the sum of its proper divisors (1).
138095537 is an equidigital number, since it uses as much as digits as its factorization.
138095537 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 113400, while the sum is 41.
The square root of 138095537 is about 11751.4057456970. The cubic root of 138095537 is about 516.8841493477.
The spelling of 138095537 in words is "one hundred thirty-eight million, ninety-five thousand, five hundred thirty-seven".
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