Base | Representation |
---|---|
bin | 1000000010100000000… |
… | …1011010000110001011 |
3 | 111012111011002211010212 |
4 | 2000220001122012023 |
5 | 4230322231124042 |
6 | 143240321231335 |
7 | 12656335060622 |
oct | 2005001320613 |
9 | 435434084125 |
10 | 138110411147 |
11 | 536327aa065 |
12 | 22924a9254b |
13 | 10040265197 |
14 | 69826b46b9 |
15 | 38d4dbd482 |
hex | 202805a18b |
138110411147 has 2 divisors, whose sum is σ = 138110411148. Its totient is φ = 138110411146.
The previous prime is 138110411141. The next prime is 138110411177. The reversal of 138110411147 is 741114011831.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 138110411147 - 26 = 138110411083 is a prime.
It is not a weakly prime, because it can be changed into another prime (138110411141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69055205573 + 69055205574.
It is an arithmetic number, because the mean of its divisors is an integer number (69055205574).
Almost surely, 2138110411147 is an apocalyptic number.
138110411147 is a deficient number, since it is larger than the sum of its proper divisors (1).
138110411147 is an equidigital number, since it uses as much as digits as its factorization.
138110411147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2688, while the sum is 32.
Adding to 138110411147 its reverse (741114011831), we get a palindrome (879224422978).
The spelling of 138110411147 in words is "one hundred thirty-eight billion, one hundred ten million, four hundred eleven thousand, one hundred forty-seven".
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