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13811102430001 is a prime number
BaseRepresentation
bin1100100011111010010111…
…0110101011001100110001
31210220022212110211011001021
43020332211312223030301
53302240114210230001
645212422144335441
72623550664452122
oct310764566531461
953808773734037
1013811102430001
11444528a2a3478
121670826314581
137924c5b43ca6
1435a664ac2049
1518e3d24ecba1
hexc8fa5dab331

13811102430001 has 2 divisors, whose sum is σ = 13811102430002. Its totient is φ = 13811102430000.

The previous prime is 13811102429963. The next prime is 13811102430007. The reversal of 13811102430001 is 10003420111831.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13570021430001 + 241081000000 = 3683751^2 + 491000^2 .

It is a cyclic number.

It is not a de Polignac number, because 13811102430001 - 215 = 13811102397233 is a prime.

It is not a weakly prime, because it can be changed into another prime (13811102430007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6905551215000 + 6905551215001.

It is an arithmetic number, because the mean of its divisors is an integer number (6905551215001).

Almost surely, 213811102430001 is an apocalyptic number.

It is an amenable number.

13811102430001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13811102430001 is an equidigital number, since it uses as much as digits as its factorization.

13811102430001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 13811102430001 its reverse (10003420111831), we get a palindrome (23814522541832).

The spelling of 13811102430001 in words is "thirteen trillion, eight hundred eleven billion, one hundred two million, four hundred thirty thousand, one".