Base | Representation |
---|---|
bin | 1100100011111010010111… |
… | …0110101011001100110001 |
3 | 1210220022212110211011001021 |
4 | 3020332211312223030301 |
5 | 3302240114210230001 |
6 | 45212422144335441 |
7 | 2623550664452122 |
oct | 310764566531461 |
9 | 53808773734037 |
10 | 13811102430001 |
11 | 444528a2a3478 |
12 | 1670826314581 |
13 | 7924c5b43ca6 |
14 | 35a664ac2049 |
15 | 18e3d24ecba1 |
hex | c8fa5dab331 |
13811102430001 has 2 divisors, whose sum is σ = 13811102430002. Its totient is φ = 13811102430000.
The previous prime is 13811102429963. The next prime is 13811102430007. The reversal of 13811102430001 is 10003420111831.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13570021430001 + 241081000000 = 3683751^2 + 491000^2 .
It is a cyclic number.
It is not a de Polignac number, because 13811102430001 - 215 = 13811102397233 is a prime.
It is not a weakly prime, because it can be changed into another prime (13811102430007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6905551215000 + 6905551215001.
It is an arithmetic number, because the mean of its divisors is an integer number (6905551215001).
Almost surely, 213811102430001 is an apocalyptic number.
It is an amenable number.
13811102430001 is a deficient number, since it is larger than the sum of its proper divisors (1).
13811102430001 is an equidigital number, since it uses as much as digits as its factorization.
13811102430001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 25.
Adding to 13811102430001 its reverse (10003420111831), we get a palindrome (23814522541832).
The spelling of 13811102430001 in words is "thirteen trillion, eight hundred eleven billion, one hundred two million, four hundred thirty thousand, one".
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