Base | Representation |
---|---|
bin | 1100100011111111010111… |
… | …1110001100110110000100 |
3 | 1210220110100011002001100021 |
4 | 3020333311332030312010 |
5 | 3302300342311030400 |
6 | 45213203402224524 |
7 | 2623626205524100 |
oct | 310776576146604 |
9 | 53813304061307 |
10 | 13812446580100 |
11 | 444590a006323 |
12 | 1670b404b5144 |
13 | 79267b46978c |
14 | 35a751416900 |
15 | 18e46050e71a |
hex | c8ff5f8cd84 |
13812446580100 has 81 divisors (see below), whose sum is σ = 34867218301167. Its totient is φ = 4735606774080.
The previous prime is 13812446580061. The next prime is 13812446580131. The reversal of 13812446580100 is 108564421831.
The square root of 13812446580100 is 3716510.
It is a perfect power (a square), and thus also a powerful number.
It can be written as a sum of positive squares in 4 ways, for example, as 248723633284 + 13563722946816 = 498722^2 + 3682896^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 26 ways as a sum of consecutive naturals, for example, 260129154 + ... + 260182246.
Almost surely, 213812446580100 is an apocalyptic number.
13812446580100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13812446580100 is the 3716510-th square number.
It is an amenable number.
13812446580100 is an abundant number, since it is smaller than the sum of its proper divisors (21054771721067).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13812446580100 is an frugal number, since it uses more digits than its factorization.
13812446580100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 106214 (or 53107 counting only the distinct ones).
The product of its (nonzero) digits is 184320, while the sum is 43.
The spelling of 13812446580100 in words is "thirteen trillion, eight hundred twelve billion, four hundred forty-six million, five hundred eighty thousand, one hundred".
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