Base | Representation |
---|---|
bin | 10100001000001001010… |
… | …101101111011000001100 |
3 | 11220020010010201010112220 |
4 | 110020021111233120030 |
5 | 140130130324211330 |
6 | 2535223132055340 |
7 | 201633255256341 |
oct | 24101125573014 |
9 | 4806103633486 |
10 | 1383136163340 |
11 | 4936483401a8 |
12 | 1a4089604550 |
13 | a0576ba96b9 |
14 | 4ad30a527c8 |
15 | 25ea28d2710 |
hex | 1420956f60c |
1383136163340 has 48 divisors (see below), whose sum is σ = 4006325443680. Its totient is φ = 356117816320.
The previous prime is 1383136163323. The next prime is 1383136163371. The reversal of 1383136163340 is 433616313831.
It is a junction number, because it is equal to n+sod(n) for n = 1383136163292 and 1383136163301.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 397451181 + ... + 397454660.
It is an arithmetic number, because the mean of its divisors is an integer number (83465113410).
Almost surely, 21383136163340 is an apocalyptic number.
1383136163340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1383136163340 is an abundant number, since it is smaller than the sum of its proper divisors (2623189280340).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1383136163340 is a wasteful number, since it uses less digits than its factorization.
1383136163340 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 794905882 (or 794905880 counting only the distinct ones).
The product of its (nonzero) digits is 279936, while the sum is 42.
The spelling of 1383136163340 in words is "one trillion, three hundred eighty-three billion, one hundred thirty-six million, one hundred sixty-three thousand, three hundred forty".
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