Base | Representation |
---|---|
bin | 1000000011010011001… |
… | …0000000001000110111 |
3 | 111020001001220110120012 |
4 | 2000310302000020313 |
5 | 4231242031221341 |
6 | 143313445330435 |
7 | 12664544436026 |
oct | 2006462001067 |
9 | 436031813505 |
10 | 138324476471 |
11 | 53732619555 |
12 | 22984706a1b |
13 | 1007570555c |
14 | 69a2cb88bd |
15 | 38e8aa50eb |
hex | 2034c80237 |
138324476471 has 2 divisors, whose sum is σ = 138324476472. Its totient is φ = 138324476470.
The previous prime is 138324476447. The next prime is 138324476557. The reversal of 138324476471 is 174674423831.
It is a weak prime.
It is an emirp because it is prime and its reverse (174674423831) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-138324476471 is a prime.
It is a super-3 number, since 3×1383244764713 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (138324476441) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69162238235 + 69162238236.
It is an arithmetic number, because the mean of its divisors is an integer number (69162238236).
Almost surely, 2138324476471 is an apocalyptic number.
138324476471 is a deficient number, since it is larger than the sum of its proper divisors (1).
138324476471 is an equidigital number, since it uses as much as digits as its factorization.
138324476471 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2709504, while the sum is 50.
The spelling of 138324476471 in words is "one hundred thirty-eight billion, three hundred twenty-four million, four hundred seventy-six thousand, four hundred seventy-one".
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