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13839312334553 is a prime number
BaseRepresentation
bin1100100101100011011101…
…0010111010111011011001
31211000000200110201210002222
43021120313102322323121
53303220402424201203
645233405312433425
72625600026624606
oct311306722727331
954000613653088
1013839312334553
114456246028282
121676199848875
137950703a62c4
1435bb7d4b16ad
1518eed3dc8038
hexc96374baed9

13839312334553 has 2 divisors, whose sum is σ = 13839312334554. Its totient is φ = 13839312334552.

The previous prime is 13839312334531. The next prime is 13839312334559. The reversal of 13839312334553 is 35543321393831.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12978633092569 + 860679241984 = 3602587^2 + 927728^2 .

It is an emirp because it is prime and its reverse (35543321393831) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13839312334553 - 218 = 13839312072409 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13839312334495 and 13839312334504.

It is not a weakly prime, because it can be changed into another prime (13839312334559) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6919656167276 + 6919656167277.

It is an arithmetic number, because the mean of its divisors is an integer number (6919656167277).

Almost surely, 213839312334553 is an apocalyptic number.

It is an amenable number.

13839312334553 is a deficient number, since it is larger than the sum of its proper divisors (1).

13839312334553 is an equidigital number, since it uses as much as digits as its factorization.

13839312334553 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10497600, while the sum is 53.

The spelling of 13839312334553 in words is "thirteen trillion, eight hundred thirty-nine billion, three hundred twelve million, three hundred thirty-four thousand, five hundred fifty-three".