Base | Representation |
---|---|
bin | 1100100101101110011101… |
… | …0011100000000001001101 |
3 | 1211000022022021012202220222 |
4 | 3021123213103200001031 |
5 | 3303242424402321433 |
6 | 45235014320321125 |
7 | 2626033144335023 |
oct | 311334723400115 |
9 | 54008267182828 |
10 | 13842265276493 |
11 | 4457520977265 |
12 | 16768827731a5 |
13 | 7954210c2524 |
14 | 35bd7d748713 |
15 | 190108273b98 |
hex | c96e74e004d |
13842265276493 has 2 divisors, whose sum is σ = 13842265276494. Its totient is φ = 13842265276492.
The previous prime is 13842265276429. The next prime is 13842265276517. The reversal of 13842265276493 is 39467256224831.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7682725563529 + 6159539712964 = 2771773^2 + 2481842^2 .
It is a cyclic number.
It is not a de Polignac number, because 13842265276493 - 26 = 13842265276429 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13842265276423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6921132638246 + 6921132638247.
It is an arithmetic number, because the mean of its divisors is an integer number (6921132638247).
Almost surely, 213842265276493 is an apocalyptic number.
It is an amenable number.
13842265276493 is a deficient number, since it is larger than the sum of its proper divisors (1).
13842265276493 is an equidigital number, since it uses as much as digits as its factorization.
13842265276493 is an evil number, because the sum of its binary digits is even.
The product of its digits is 104509440, while the sum is 62.
The spelling of 13842265276493 in words is "thirteen trillion, eight hundred forty-two billion, two hundred sixty-five million, two hundred seventy-six thousand, four hundred ninety-three".
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