Base | Representation |
---|---|
bin | 1100100110011000001110… |
… | …1010110001100010110111 |
3 | 1211001101020201222111012222 |
4 | 3021212003222301202313 |
5 | 3303433411002323004 |
6 | 45244111124032555 |
7 | 2626611053552342 |
oct | 311460352614267 |
9 | 54041221874188 |
10 | 13853478557879 |
11 | 4461255539564 |
12 | 1678a91b3275b |
13 | 7964ba27447c |
14 | 35c724a97459 |
15 | 1905628e27be |
hex | c9983ab18b7 |
13853478557879 has 2 divisors, whose sum is σ = 13853478557880. Its totient is φ = 13853478557878.
The previous prime is 13853478557839. The next prime is 13853478557909. The reversal of 13853478557879 is 97875587435831.
13853478557879 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13853478557879 - 28 = 13853478557623 is a prime.
It is a super-2 number, since 2×138534785578792 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13853478557839) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6926739278939 + 6926739278940.
It is an arithmetic number, because the mean of its divisors is an integer number (6926739278940).
Almost surely, 213853478557879 is an apocalyptic number.
13853478557879 is a deficient number, since it is larger than the sum of its proper divisors (1).
13853478557879 is an equidigital number, since it uses as much as digits as its factorization.
13853478557879 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7112448000, while the sum is 80.
The spelling of 13853478557879 in words is "thirteen trillion, eight hundred fifty-three billion, four hundred seventy-eight million, five hundred fifty-seven thousand, eight hundred seventy-nine".
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