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138613785251 is a prime number
BaseRepresentation
bin1000000100011000000…
…1101000001010100011
3111020210020021212121012
42001012001220022203
54232340112112001
6143402302251135
713004656506614
oct2010601501243
9436706255535
10138613785251
1153870960517
1222a45586aab
13100c062bc96
1469cd4a7c0b
1539141a12bb
hex20460682a3

138613785251 has 2 divisors, whose sum is σ = 138613785252. Its totient is φ = 138613785250.

The previous prime is 138613785223. The next prime is 138613785253. The reversal of 138613785251 is 152587316831.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 138613785251 - 26 = 138613785187 is a prime.

It is a super-2 number, since 2×1386137852512 (a number of 23 digits) contains 22 as substring.

Together with 138613785253, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 138613785251.

It is not a weakly prime, because it can be changed into another prime (138613785253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69306892625 + 69306892626.

It is an arithmetic number, because the mean of its divisors is an integer number (69306892626).

Almost surely, 2138613785251 is an apocalyptic number.

138613785251 is a deficient number, since it is larger than the sum of its proper divisors (1).

138613785251 is an equidigital number, since it uses as much as digits as its factorization.

138613785251 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1209600, while the sum is 50.

The spelling of 138613785251 in words is "one hundred thirty-eight billion, six hundred thirteen million, seven hundred eighty-five thousand, two hundred fifty-one".