138719543 has 2 divisors, whose sum is σ = 138719544. Its totient is φ = 138719542.

The previous prime is 138719533. The next prime is 138719563. The reversal of 138719543 is 345917831.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 138719543 - 2⁶ = 138719479 is a prime.

It is a super-2 number, since 2×138719543² = 38486223220257698, which contains 22 as substring.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 138719543.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (138719533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69359771 + 69359772.

It is an arithmetic number, because the mean of its divisors is an integer number (69359772).

Almost surely, 2^138719543 is an apocalyptic number.

138719543 is a deficient number, since it is larger than the sum of its proper divisors (1).

138719543 is an equidigital number, since it uses as much as digits as its factorization.

138719543 is an evil number, because the sum of its binary digits is even.

The product of its digits is 90720, while the sum is 41.

The square root of 138719543 is about 11777.9260907853. The cubic root of 138719543 is about 517.6615199024.

The spelling of 138719543 in words is "one hundred thirty-eight million, seven hundred nineteen thousand, five hundred forty-three".