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13879391442533 is a prime number
BaseRepresentation
bin1100100111111000110000…
…1100100101011001100101
31211010212010122122102100122
43021332030030211121211
53304344443202130113
645304034315051325
72631516154465121
oct311761414453145
954125118572318
1013879391442533
1144712426a8311
121681b04140b45
13798a89965c06
1435daa2392581
1519107c7d9408
hexc9f8c325665

13879391442533 has 2 divisors, whose sum is σ = 13879391442534. Its totient is φ = 13879391442532.

The previous prime is 13879391442509. The next prime is 13879391442547. The reversal of 13879391442533 is 33524419397831.

13879391442533 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8087778585604 + 5791612856929 = 2843902^2 + 2406577^2 .

It is a cyclic number.

It is not a de Polignac number, because 13879391442533 - 28 = 13879391442277 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13879391402533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6939695721266 + 6939695721267.

It is an arithmetic number, because the mean of its divisors is an integer number (6939695721267).

Almost surely, 213879391442533 is an apocalyptic number.

It is an amenable number.

13879391442533 is a deficient number, since it is larger than the sum of its proper divisors (1).

13879391442533 is an equidigital number, since it uses as much as digits as its factorization.

13879391442533 is an evil number, because the sum of its binary digits is even.

The product of its digits is 58786560, while the sum is 62.

The spelling of 13879391442533 in words is "thirteen trillion, eight hundred seventy-nine billion, three hundred ninety-one million, four hundred forty-two thousand, five hundred thirty-three".