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138845510750783 is a prime number
BaseRepresentation
bin11111100100011101111101…
…010110001101001000111111
3200012121111112101001010001002
4133210131331112031020333
5121144321101223011113
61211144425211440515
741150154122422454
oct3744357526151077
9605544471033032
10138845510750783
114027106113a891
12136a523475613b
135c620c9ab4435
1426402311c582b
15110ba54eccc58
hex7e477d58d23f

138845510750783 has 2 divisors, whose sum is σ = 138845510750784. Its totient is φ = 138845510750782.

The previous prime is 138845510750549. The next prime is 138845510750827. The reversal of 138845510750783 is 387057015548831.

It is a strong prime.

It is an emirp because it is prime and its reverse (387057015548831) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-138845510750783 is a prime.

It is a super-2 number, since 2×1388455107507832 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (138845510750383) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69422755375391 + 69422755375392.

It is an arithmetic number, because the mean of its divisors is an integer number (69422755375392).

Almost surely, 2138845510750783 is an apocalyptic number.

138845510750783 is a deficient number, since it is larger than the sum of its proper divisors (1).

138845510750783 is an equidigital number, since it uses as much as digits as its factorization.

138845510750783 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 112896000, while the sum is 65.

The spelling of 138845510750783 in words is "one hundred thirty-eight trillion, eight hundred forty-five billion, five hundred ten million, seven hundred fifty thousand, seven hundred eighty-three".