Base | Representation |
---|---|
bin | 11001110111110111… |
… | …11110001110010001 |
3 | 1022212001101102222221 |
4 | 30323323332032101 |
5 | 211421430311433 |
6 | 10214201101041 |
7 | 1001135060206 |
oct | 147373761621 |
9 | 38761342887 |
10 | 13890478993 |
11 | 59888a4506 |
12 | 2837a87781 |
13 | 1404a13851 |
14 | 95ab27cad |
15 | 5646ec72d |
hex | 33befe391 |
13890478993 has 2 divisors, whose sum is σ = 13890478994. Its totient is φ = 13890478992.
The previous prime is 13890478991. The next prime is 13890478999. The reversal of 13890478993 is 39987409831.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13555479184 + 334999809 = 116428^2 + 18303^2 .
It is a cyclic number.
It is not a de Polignac number, because 13890478993 - 21 = 13890478991 is a prime.
Together with 13890478991, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13890478991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6945239496 + 6945239497.
It is an arithmetic number, because the mean of its divisors is an integer number (6945239497).
Almost surely, 213890478993 is an apocalyptic number.
It is an amenable number.
13890478993 is a deficient number, since it is larger than the sum of its proper divisors (1).
13890478993 is an equidigital number, since it uses as much as digits as its factorization.
13890478993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11757312, while the sum is 61.
The spelling of 13890478993 in words is "thirteen billion, eight hundred ninety million, four hundred seventy-eight thousand, nine hundred ninety-three".
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