Base | Representation |
---|---|
bin | 11111100101111100000011… |
… | …010010110000111101000010 |
3 | 200012222011022102121201111022 |
4 | 133211330003102300331002 |
5 | 121203000004303244100 |
6 | 1211303054343145442 |
7 | 41160361563066011 |
oct | 3745740322607502 |
9 | 605864272551438 |
10 | 138946542243650 |
11 | 402aa996849829 |
12 | 1370092ba45282 |
13 | 5c6b7ab20968b |
14 | 2645097230a78 |
15 | 110e4b9a69e85 |
hex | 7e5f034b0f42 |
138946542243650 has 48 divisors (see below), whose sum is σ = 258778505740608. Its totient is φ = 55505989752000.
The previous prime is 138946542243631. The next prime is 138946542243653. The reversal of 138946542243650 is 56342245649831.
It is a super-3 number, since 3×1389465422436503 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (138946542243653) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 116682755 + ... + 117867545.
It is an arithmetic number, because the mean of its divisors is an integer number (5391218869596).
Almost surely, 2138946542243650 is an apocalyptic number.
138946542243650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
138946542243650 is a deficient number, since it is larger than the sum of its proper divisors (119831963496958).
138946542243650 is a wasteful number, since it uses less digits than its factorization.
138946542243650 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1187867 (or 1187862 counting only the distinct ones).
The product of its (nonzero) digits is 149299200, while the sum is 62.
The spelling of 138946542243650 in words is "one hundred thirty-eight trillion, nine hundred forty-six billion, five hundred forty-two million, two hundred forty-three thousand, six hundred fifty".
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