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13899504797 is a prime number
BaseRepresentation
bin11001111000111100…
…11001110010011101
31022212200101000001222
430330132121302131
5211431233123142
610215122343125
71001304561413
oct147436316235
938780330058
1013899504797
1159929a9752
12283aabaaa5
131406853b69
1495bdd72b3
155653d1bd2
hex33c799c9d

13899504797 has 2 divisors, whose sum is σ = 13899504798. Its totient is φ = 13899504796.

The previous prime is 13899504757. The next prime is 13899504863. The reversal of 13899504797 is 79740599831.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11240452441 + 2659052356 = 106021^2 + 51566^2 .

It is an emirp because it is prime and its reverse (79740599831) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13899504797 - 26 = 13899504733 is a prime.

It is a super-2 number, since 2×138995047972 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13899504757) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6949752398 + 6949752399.

It is an arithmetic number, because the mean of its divisors is an integer number (6949752399).

Almost surely, 213899504797 is an apocalyptic number.

It is an amenable number.

13899504797 is a deficient number, since it is larger than the sum of its proper divisors (1).

13899504797 is an equidigital number, since it uses as much as digits as its factorization.

13899504797 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17146080, while the sum is 62.

The spelling of 13899504797 in words is "thirteen billion, eight hundred ninety-nine million, five hundred four thousand, seven hundred ninety-seven".