Base | Representation |
---|---|
bin | 11001111000111101… |
… | …10001000010000111 |
3 | 1022212200112211200021 |
4 | 30330132301002013 |
5 | 211431244200012 |
6 | 10215124400011 |
7 | 1001305436116 |
oct | 147436610207 |
9 | 38780484607 |
10 | 13899600007 |
11 | 5992a64237 |
12 | 283ab46007 |
13 | 14068882b7 |
14 | 95c01dc7d |
15 | 565400007 |
hex | 33c7b1087 |
13899600007 has 2 divisors, whose sum is σ = 13899600008. Its totient is φ = 13899600006.
The previous prime is 13899599999. The next prime is 13899600053. The reversal of 13899600007 is 70000699831.
13899600007 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (70000699831) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13899600007 - 23 = 13899599999 is a prime.
It is a super-4 number, since 4×138996000074 (a number of 42 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13899600067) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6949800003 + 6949800004.
It is an arithmetic number, because the mean of its divisors is an integer number (6949800004).
Almost surely, 213899600007 is an apocalyptic number.
13899600007 is a deficient number, since it is larger than the sum of its proper divisors (1).
13899600007 is an equidigital number, since it uses as much as digits as its factorization.
13899600007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81648, while the sum is 43.
The spelling of 13899600007 in words is "thirteen billion, eight hundred ninety-nine million, six hundred thousand, seven".
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