Base | Representation |
---|---|
bin | 10100010000100011010… |
… | …001010001100001101111 |
3 | 11221002102002210011211112 |
4 | 110100203101101201233 |
5 | 140302121222302303 |
6 | 2543314444342235 |
7 | 202403023253243 |
oct | 24204321214157 |
9 | 4832362704745 |
10 | 1392161134703 |
11 | 497459737819 |
12 | 1a5987b4497b |
13 | a1384890b41 |
14 | 4b5494c8423 |
15 | 2632ed930d8 |
hex | 1442345186f |
1392161134703 has 2 divisors, whose sum is σ = 1392161134704. Its totient is φ = 1392161134702.
The previous prime is 1392161134699. The next prime is 1392161134717. The reversal of 1392161134703 is 3074311612931.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1392161134703 - 22 = 1392161134699 is a prime.
It is a super-2 number, since 2×13921611347032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1392161134723) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 696080567351 + 696080567352.
It is an arithmetic number, because the mean of its divisors is an integer number (696080567352).
Almost surely, 21392161134703 is an apocalyptic number.
1392161134703 is a deficient number, since it is larger than the sum of its proper divisors (1).
1392161134703 is an equidigital number, since it uses as much as digits as its factorization.
1392161134703 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81648, while the sum is 41.
The spelling of 1392161134703 in words is "one trillion, three hundred ninety-two billion, one hundred sixty-one million, one hundred thirty-four thousand, seven hundred three".
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