13922834081657 has 2 divisors, whose sum is σ = 13922834081658. Its totient is φ = 13922834081656.

The previous prime is 13922834081647. The next prime is 13922834081659. The reversal of 13922834081657 is 75618043822931.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11864366691961 + 2058467389696 = 3444469^2 + 1434736^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13922834081657 is a prime.

Together with 13922834081659, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13922834081596 and 13922834081605.

It is not a weakly prime, because it can be changed into another prime (13922834081659) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6961417040828 + 6961417040829.

It is an arithmetic number, because the mean of its divisors is an integer number (6961417040829).

It is a 1-persistent number, because it is pandigital, but 2⋅13922834081657 = 27845668163314 is not.

Almost surely, 2^{13922834081657} is an apocalyptic number.

It is an amenable number.

13922834081657 is a deficient number, since it is larger than the sum of its proper divisors (1).

13922834081657 is an equidigital number, since it uses as much as digits as its factorization.

13922834081657 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17418240, while the sum is 59.

The spelling of 13922834081657 in words is "thirteen trillion, nine hundred twenty-two billion, eight hundred thirty-four million, eighty-one thousand, six hundred fifty-seven".