Base | Representation |
---|---|
bin | 101001011111110… |
… | …1011100010011001 |
3 | 10121001002112011111 |
4 | 1102333223202121 |
5 | 10322430100423 |
6 | 350100300321 |
7 | 46335263302 |
oct | 12277534231 |
9 | 3531075144 |
10 | 1392425113 |
11 | 654a95662 |
12 | 32a3a16a1 |
13 | 1926289b1 |
14 | d2cdd7a9 |
15 | 8239a60d |
hex | 52feb899 |
1392425113 has 2 divisors, whose sum is σ = 1392425114. Its totient is φ = 1392425112.
The previous prime is 1392425077. The next prime is 1392425143. The reversal of 1392425113 is 3115242931.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1252310544 + 140114569 = 35388^2 + 11837^2 .
It is a cyclic number.
It is not a de Polignac number, because 1392425113 - 29 = 1392424601 is a prime.
It is not a weakly prime, because it can be changed into another prime (1392425143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 696212556 + 696212557.
It is an arithmetic number, because the mean of its divisors is an integer number (696212557).
Almost surely, 21392425113 is an apocalyptic number.
It is an amenable number.
1392425113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1392425113 is an equidigital number, since it uses as much as digits as its factorization.
1392425113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6480, while the sum is 31.
The square root of 1392425113 is about 37315.2128896513. The cubic root of 1392425113 is about 1116.6676869474.
The spelling of 1392425113 in words is "one billion, three hundred ninety-two million, four hundred twenty-five thousand, one hundred thirteen".
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