Base | Representation |
---|---|
bin | 11001111101101011… |
… | …00001110000100111 |
3 | 1022222102220201112211 |
4 | 30332311201300213 |
5 | 212021403334231 |
6 | 10223055424251 |
7 | 1002265401202 |
oct | 147665416047 |
9 | 38872821484 |
10 | 13939121191 |
11 | 5a032a8076 |
12 | 2850225087 |
13 | 1411b14c08 |
14 | 96338a939 |
15 | 568b09eb1 |
hex | 33ed61c27 |
13939121191 has 2 divisors, whose sum is σ = 13939121192. Its totient is φ = 13939121190.
The previous prime is 13939121173. The next prime is 13939121197. The reversal of 13939121191 is 19112193931.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13939121191 - 25 = 13939121159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13939121197) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6969560595 + 6969560596.
It is an arithmetic number, because the mean of its divisors is an integer number (6969560596).
Almost surely, 213939121191 is an apocalyptic number.
13939121191 is a deficient number, since it is larger than the sum of its proper divisors (1).
13939121191 is an equidigital number, since it uses as much as digits as its factorization.
13939121191 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 13122, while the sum is 40.
The spelling of 13939121191 in words is "thirteen billion, nine hundred thirty-nine million, one hundred twenty-one thousand, one hundred ninety-one".
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