Base | Representation |
---|---|
bin | 1000001000000010100… |
… | …1010010001111111101 |
3 | 111100022202212120000111 |
4 | 2002000221102033331 |
5 | 4241343344303043 |
6 | 144044033430021 |
7 | 13041231062356 |
oct | 2020051221775 |
9 | 440282776014 |
10 | 139597259773 |
11 | 54226017484 |
12 | 2307aa0b311 |
13 | 1021930137a |
14 | 6a83d52d2d |
15 | 39706bb09d |
hex | 2080a523fd |
139597259773 has 2 divisors, whose sum is σ = 139597259774. Its totient is φ = 139597259772.
The previous prime is 139597259713. The next prime is 139597259779. The reversal of 139597259773 is 377952795931.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 113086256089 + 26511003684 = 336283^2 + 162822^2 .
It is a cyclic number.
It is not a de Polignac number, because 139597259773 - 229 = 139060388861 is a prime.
It is a super-2 number, since 2×1395972597732 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 139597259699 and 139597259708.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (139597259779) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69798629886 + 69798629887.
It is an arithmetic number, because the mean of its divisors is an integer number (69798629887).
Almost surely, 2139597259773 is an apocalyptic number.
It is an amenable number.
139597259773 is a deficient number, since it is larger than the sum of its proper divisors (1).
139597259773 is an equidigital number, since it uses as much as digits as its factorization.
139597259773 is an evil number, because the sum of its binary digits is even.
The product of its digits is 112521150, while the sum is 67.
The spelling of 139597259773 in words is "one hundred thirty-nine billion, five hundred ninety-seven million, two hundred fifty-nine thousand, seven hundred seventy-three".
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