Base | Representation |
---|---|
bin | 1100101101001000101110… |
… | …0010111111101011000101 |
3 | 1211110110220200122100202222 |
4 | 3023102023202333223011 |
5 | 3312334142130301232 |
6 | 45413311210342125 |
7 | 2641161042024026 |
oct | 313221342775305 |
9 | 54413820570688 |
10 | 13969574853317 |
11 | 44a6510900666 |
12 | 169749242a945 |
13 | 7a442c784685 |
14 | 3641b9794c4d |
15 | 1935a9ce4d12 |
hex | cb48b8bfac5 |
13969574853317 has 2 divisors, whose sum is σ = 13969574853318. Its totient is φ = 13969574853316.
The previous prime is 13969574853287. The next prime is 13969574853337. The reversal of 13969574853317 is 71335847596931.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12982480940641 + 987093912676 = 3603121^2 + 993526^2 .
It is a cyclic number.
It is not a de Polignac number, because 13969574853317 - 28 = 13969574853061 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13969574853337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6984787426658 + 6984787426659.
It is an arithmetic number, because the mean of its divisors is an integer number (6984787426659).
Almost surely, 213969574853317 is an apocalyptic number.
It is an amenable number.
13969574853317 is a deficient number, since it is larger than the sum of its proper divisors (1).
13969574853317 is an equidigital number, since it uses as much as digits as its factorization.
13969574853317 is an evil number, because the sum of its binary digits is even.
The product of its digits is 514382400, while the sum is 71.
The spelling of 13969574853317 in words is "thirteen trillion, nine hundred sixty-nine billion, five hundred seventy-four million, eight hundred fifty-three thousand, three hundred seventeen".
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