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139726493650 = 2522794529873
BaseRepresentation
bin1000001000100001011…
…0010001011111010010
3111100122210001022120101
42002020112101133102
54242124440244100
6144104531403014
713044360412462
oct2021026213722
9440583038511
10139726493650
1154291a65837
12230b615346a
131023a00c213
146a97193ba2
15397bbe786a
hex20885917d2

139726493650 has 12 divisors (see below), whose sum is σ = 259891278282. Its totient is φ = 55890597440.

The previous prime is 139726493609. The next prime is 139726493681. The reversal of 139726493650 is 56394627931.

It can be written as a sum of positive squares in 3 ways, for example, as 129343087449 + 10383406201 = 359643^2 + 101899^2 .

It is a junction number, because it is equal to n+sod(n) for n = 139726493591 and 139726493600.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1397264887 + ... + 1397264986.

Almost surely, 2139726493650 is an apocalyptic number.

139726493650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

139726493650 is a deficient number, since it is larger than the sum of its proper divisors (120164784632).

139726493650 is a wasteful number, since it uses less digits than its factorization.

139726493650 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2794529885 (or 2794529880 counting only the distinct ones).

The product of its (nonzero) digits is 7348320, while the sum is 55.

The spelling of 139726493650 in words is "one hundred thirty-nine billion, seven hundred twenty-six million, four hundred ninety-three thousand, six hundred fifty".

Divisors: 1 2 5 10 25 50 2794529873 5589059746 13972649365 27945298730 69863246825 139726493650