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13972929253 is a prime number
BaseRepresentation
bin11010000001101100…
…11111101011100101
31100001210112100111021
431000312133223211
5212104032214003
610230304211141
71003155640033
oct150066375345
940053470437
1013972929253
115a20399618
12285b609ab1
131418b2129a
14967a6b553
1556ba872bd
hex340d9fae5

13972929253 has 2 divisors, whose sum is σ = 13972929254. Its totient is φ = 13972929252.

The previous prime is 13972929241. The next prime is 13972929277. The reversal of 13972929253 is 35292927931.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7495576929 + 6477352324 = 86577^2 + 80482^2 .

It is an emirp because it is prime and its reverse (35292927931) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13972929253 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13972929253.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13972929353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6986464626 + 6986464627.

It is an arithmetic number, because the mean of its divisors is an integer number (6986464627).

Almost surely, 213972929253 is an apocalyptic number.

It is an amenable number.

13972929253 is a deficient number, since it is larger than the sum of its proper divisors (1).

13972929253 is an equidigital number, since it uses as much as digits as its factorization.

13972929253 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1837080, while the sum is 52.

The spelling of 13972929253 in words is "thirteen billion, nine hundred seventy-two million, nine hundred twenty-nine thousand, two hundred fifty-three".