Base | Representation |
---|---|
bin | 101001101010010… |
… | …1111111010010101 |
3 | 10121102111010012211 |
4 | 1103110233322111 |
5 | 10330333314203 |
6 | 350414513421 |
7 | 46433235205 |
oct | 12324577225 |
9 | 3542433184 |
10 | 1397948053 |
11 | 658118077 |
12 | 330205871 |
13 | 1938107c8 |
14 | d393a405 |
15 | 82adbc6d |
hex | 5352fe95 |
1397948053 has 2 divisors, whose sum is σ = 1397948054. Its totient is φ = 1397948052.
The previous prime is 1397948021. The next prime is 1397948081. The reversal of 1397948053 is 3508497931.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1291899249 + 106048804 = 35943^2 + 10298^2 .
It is a cyclic number.
It is not a de Polignac number, because 1397948053 - 25 = 1397948021 is a prime.
It is a super-3 number, since 3×13979480533 (a number of 28 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1397947988 and 1397948006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1397948353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 698974026 + 698974027.
It is an arithmetic number, because the mean of its divisors is an integer number (698974027).
Almost surely, 21397948053 is an apocalyptic number.
It is an amenable number.
1397948053 is a deficient number, since it is larger than the sum of its proper divisors (1).
1397948053 is an equidigital number, since it uses as much as digits as its factorization.
1397948053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 816480, while the sum is 49.
The square root of 1397948053 is about 37389.1435178716. The cubic root of 1397948053 is about 1118.1421295064.
The spelling of 1397948053 in words is "one billion, three hundred ninety-seven million, nine hundred forty-eight thousand, fifty-three".
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