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13980403 is a prime number
BaseRepresentation
bin110101010101…
…001011110011
3222022021111201
4311111023303
512034333103
61215352031
7226555123
oct65251363
928267451
1013980403
117989758
124822617
132b86538
141bdcc83
15136251d
hexd552f3

13980403 has 2 divisors, whose sum is σ = 13980404. Its totient is φ = 13980402.

The previous prime is 13980401. The next prime is 13980427. The reversal of 13980403 is 30408931.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13980403 - 21 = 13980401 is a prime.

Together with 13980401, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13980401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6990201 + 6990202.

It is an arithmetic number, because the mean of its divisors is an integer number (6990202).

Almost surely, 213980403 is an apocalyptic number.

13980403 is a deficient number, since it is larger than the sum of its proper divisors (1).

13980403 is an equidigital number, since it uses as much as digits as its factorization.

13980403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 28.

The square root of 13980403 is about 3739.0377104276. The cubic root of 13980403 is about 240.9017178148.

The spelling of 13980403 in words is "thirteen million, nine hundred eighty thousand, four hundred three".