Base | Representation |
---|---|
bin | 11010000011100100… |
… | …10010101111011101 |
3 | 1100002220000202102112 |
4 | 31001302102233131 |
5 | 212122040324033 |
6 | 10232024203405 |
7 | 1003436115434 |
oct | 150162225735 |
9 | 40086022375 |
10 | 13988604893 |
11 | 5a2922599a |
12 | 2864909565 |
13 | 141c14c303 |
14 | 969b8c11b |
15 | 56d131c48 |
hex | 341c92bdd |
13988604893 has 2 divisors, whose sum is σ = 13988604894. Its totient is φ = 13988604892.
The previous prime is 13988604881. The next prime is 13988604913. The reversal of 13988604893 is 39840688931.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12365884804 + 1622720089 = 111202^2 + 40283^2 .
It is a cyclic number.
It is not a de Polignac number, because 13988604893 - 26 = 13988604829 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13988604493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6994302446 + 6994302447.
It is an arithmetic number, because the mean of its divisors is an integer number (6994302447).
Almost surely, 213988604893 is an apocalyptic number.
It is an amenable number.
13988604893 is a deficient number, since it is larger than the sum of its proper divisors (1).
13988604893 is an equidigital number, since it uses as much as digits as its factorization.
13988604893 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8957952, while the sum is 59.
The spelling of 13988604893 in words is "thirteen billion, nine hundred eighty-eight million, six hundred four thousand, eight hundred ninety-three".
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