Base | Representation |
---|---|
bin | 11111110100000001110100… |
… | …010101111011101010011111 |
3 | 200100101201120102201102010101 |
4 | 133310001310111323222133 |
5 | 121314331010433302314 |
6 | 1213323550315321531 |
7 | 41320340223604342 |
oct | 3764016425735237 |
9 | 610351512642111 |
10 | 139914806540959 |
11 | 406435997a255a |
12 | 138385157502a7 |
13 | 600bba9642cc8 |
14 | 2679cac8d2459 |
15 | 112978a100174 |
hex | 7f407457ba9f |
139914806540959 has 2 divisors, whose sum is σ = 139914806540960. Its totient is φ = 139914806540958.
The previous prime is 139914806540833. The next prime is 139914806540981. The reversal of 139914806540959 is 959045608419931.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 139914806540959 - 233 = 139906216606367 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 139914806540891 and 139914806540900.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (139914806540459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69957403270479 + 69957403270480.
It is an arithmetic number, because the mean of its divisors is an integer number (69957403270480).
Almost surely, 2139914806540959 is an apocalyptic number.
139914806540959 is a deficient number, since it is larger than the sum of its proper divisors (1).
139914806540959 is an equidigital number, since it uses as much as digits as its factorization.
139914806540959 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 377913600, while the sum is 73.
The spelling of 139914806540959 in words is "one hundred thirty-nine trillion, nine hundred fourteen billion, eight hundred six million, five hundred forty thousand, nine hundred fifty-nine".
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