Base | Representation |
---|---|
bin | 1000001001010110111… |
… | …0000100000111011111 |
3 | 111101020102011222212112 |
4 | 2002111232010013133 |
5 | 4243104403143033 |
6 | 144143104024235 |
7 | 13053053314421 |
oct | 2022556040737 |
9 | 441212158775 |
10 | 139950834143 |
11 | 543976630aa |
12 | 2315930207b |
13 | 10274639483 |
14 | 6ab8cb0811 |
15 | 399175dc48 |
hex | 2095b841df |
139950834143 has 2 divisors, whose sum is σ = 139950834144. Its totient is φ = 139950834142.
The previous prime is 139950834137. The next prime is 139950834161. The reversal of 139950834143 is 341438059931.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-139950834143 is a prime.
It is a super-3 number, since 3×1399508341433 (a number of 34 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 139950834091 and 139950834100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (139950834173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69975417071 + 69975417072.
It is an arithmetic number, because the mean of its divisors is an integer number (69975417072).
Almost surely, 2139950834143 is an apocalyptic number.
139950834143 is a deficient number, since it is larger than the sum of its proper divisors (1).
139950834143 is an equidigital number, since it uses as much as digits as its factorization.
139950834143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1399680, while the sum is 50.
The spelling of 139950834143 in words is "one hundred thirty-nine billion, nine hundred fifty million, eight hundred thirty-four thousand, one hundred forty-three".
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