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1399543894741 is a prime number
BaseRepresentation
bin10100010111011011010…
…100010001001011010101
311221210110121202020200111
4110113123110101023111
5140412231214112431
62550535214443021
7203054000552056
oct24273324211325
94853417666614
101399543894741
1149a5a80516a3
121a72a8503471
13a1c902802c5
144ba49bdc72d
15266130b77b1
hex145db5112d5

1399543894741 has 2 divisors, whose sum is σ = 1399543894742. Its totient is φ = 1399543894740.

The previous prime is 1399543894561. The next prime is 1399543894759. The reversal of 1399543894741 is 1474983459931.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1399302092241 + 241802500 = 1182921^2 + 15550^2 .

It is a cyclic number.

It is not a de Polignac number, because 1399543894741 - 223 = 1399535506133 is a prime.

It is a super-3 number, since 3×13995438947413 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1399543814741) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 699771947370 + 699771947371.

It is an arithmetic number, because the mean of its divisors is an integer number (699771947371).

Almost surely, 21399543894741 is an apocalyptic number.

It is an amenable number.

1399543894741 is a deficient number, since it is larger than the sum of its proper divisors (1).

1399543894741 is an equidigital number, since it uses as much as digits as its factorization.

1399543894741 is an evil number, because the sum of its binary digits is even.

The product of its digits is 117573120, while the sum is 67.

The spelling of 1399543894741 in words is "one trillion, three hundred ninety-nine billion, five hundred forty-three million, eight hundred ninety-four thousand, seven hundred forty-one".