Base | Representation |
---|---|
bin | 10100010111100011000… |
… | …001010110110111111110 |
3 | 11221210210121222100112002 |
4 | 110113203001112313332 |
5 | 140413012311430240 |
6 | 2551000113142302 |
7 | 203060130342251 |
oct | 24274301266776 |
9 | 4853717870462 |
10 | 1399673155070 |
11 | 49a664008913 |
12 | 1a732385a992 |
13 | a1cb0c9a1c8 |
14 | 4ba5d049098 |
15 | 2661e5ebd15 |
hex | 145e3056dfe |
1399673155070 has 16 divisors (see below), whose sum is σ = 2578002649200. Its totient is φ = 546849046464.
The previous prime is 1399673155063. The next prime is 1399673155073. The reversal of 1399673155070 is 705513769931.
It is a junction number, because it is equal to n+sod(n) for n = 1399673154997 and 1399673155015.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1399673155073) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1627526495 + ... + 1627527354.
It is an arithmetic number, because the mean of its divisors is an integer number (161125165575).
Almost surely, 21399673155070 is an apocalyptic number.
1399673155070 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1399673155070 is a deficient number, since it is larger than the sum of its proper divisors (1178329494130).
1399673155070 is a wasteful number, since it uses less digits than its factorization.
1399673155070 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3255053899.
The product of its (nonzero) digits is 5358150, while the sum is 56.
The spelling of 1399673155070 in words is "one trillion, three hundred ninety-nine billion, six hundred seventy-three million, one hundred fifty-five thousand, seventy".
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