14000000023 has 4 divisors (see below), whose sum is σ = 14378378440. Its totient is φ = 13621621608.

The previous prime is 13999999991. The next prime is 14000000057. The reversal of 14000000023 is 32000000041.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32000000041 = 881 ⋅36322361.

It is a cyclic number.

It is not a de Polignac number, because 14000000023 - 2⁵ = 13999999991 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13999999946 and 14000000009.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14000090023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 189189153 + ... + 189189226.

It is an arithmetic number, because the mean of its divisors is an integer number (3594594610).

Almost surely, 2^14000000023 is an apocalyptic number.

14000000023 is a deficient number, since it is larger than the sum of its proper divisors (378378417).

14000000023 is an equidigital number, since it uses as much as digits as its factorization.

14000000023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 378378416.

The product of its (nonzero) digits is 24, while the sum is 10.

Adding to 14000000023 its reverse (32000000041), we get a palindrome (46000000064).

The spelling of 14000000023 in words is "fourteen billion, twenty-three", and thus it is an aban number.