Base | Representation |
---|---|
bin | 11111110101010010011111… |
… | …100100100001100110001101 |
3 | 200100201000011110011121101201 |
4 | 133311102133210201212031 |
5 | 121322240412332220212 |
6 | 1213431434121105501 |
7 | 41326524655515151 |
oct | 3765223744414615 |
9 | 610630143147351 |
10 | 140001431132557 |
11 | 40677301054325 |
12 | 13851270028291 |
13 | 601710306c7b7 |
14 | 26801693c5061 |
15 | 112bb59e80b57 |
hex | 7f549f92198d |
140001431132557 has 2 divisors, whose sum is σ = 140001431132558. Its totient is φ = 140001431132556.
The previous prime is 140001431132411. The next prime is 140001431132561. The reversal of 140001431132557 is 755231134100041.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 135845108978121 + 4156322154436 = 11655261^2 + 2038706^2 .
It is a cyclic number.
It is not a de Polignac number, because 140001431132557 - 219 = 140001430608269 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140001431102557) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70000715566278 + 70000715566279.
It is an arithmetic number, because the mean of its divisors is an integer number (70000715566279).
Almost surely, 2140001431132557 is an apocalyptic number.
It is an amenable number.
140001431132557 is a deficient number, since it is larger than the sum of its proper divisors (1).
140001431132557 is an equidigital number, since it uses as much as digits as its factorization.
140001431132557 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50400, while the sum is 37.
Adding to 140001431132557 its reverse (755231134100041), we get a palindrome (895232565232598).
The spelling of 140001431132557 in words is "one hundred forty trillion, one billion, four hundred thirty-one million, one hundred thirty-two thousand, five hundred fifty-seven".
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