Base | Representation |
---|---|
bin | 11111110101010011011010… |
… | …100101011010110000000111 |
3 | 200100201002201110012101100011 |
4 | 133311103122211122300013 |
5 | 121322244424313104112 |
6 | 1213432120250131051 |
7 | 41326561340242402 |
oct | 3765233245326007 |
9 | 610632643171304 |
10 | 140002421222407 |
11 | 40677769a194a7 |
12 | 138514a7720a87 |
13 | 6017230219c93 |
14 | 2680220ab2d39 |
15 | 112bbb6d55aa7 |
hex | 7f54da95ac07 |
140002421222407 has 2 divisors, whose sum is σ = 140002421222408. Its totient is φ = 140002421222406.
The previous prime is 140002421222383. The next prime is 140002421222501. The reversal of 140002421222407 is 704222124200041.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-140002421222407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140002421226407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70001210611203 + 70001210611204.
It is an arithmetic number, because the mean of its divisors is an integer number (70001210611204).
Almost surely, 2140002421222407 is an apocalyptic number.
140002421222407 is a deficient number, since it is larger than the sum of its proper divisors (1).
140002421222407 is an equidigital number, since it uses as much as digits as its factorization.
140002421222407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14336, while the sum is 31.
Adding to 140002421222407 its reverse (704222124200041), we get a palindrome (844224545422448).
The spelling of 140002421222407 in words is "one hundred forty trillion, two billion, four hundred twenty-one million, two hundred twenty-two thousand, four hundred seven".
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