Base | Representation |
---|---|
bin | 1000001001100011001… |
… | …1010100011110101011 |
3 | 111101101000111002211001 |
4 | 2002120303110132223 |
5 | 4243211122343111 |
6 | 144152152215431 |
7 | 13054251661564 |
oct | 2023063243653 |
9 | 441330432731 |
10 | 140002543531 |
11 | 54413871134 |
12 | 2317269a577 |
13 | 10282272946 |
14 | 6ac1ad116b |
15 | 39960751c1 |
hex | 2098cd47ab |
140002543531 has 2 divisors, whose sum is σ = 140002543532. Its totient is φ = 140002543530.
The previous prime is 140002543519. The next prime is 140002543559. The reversal of 140002543531 is 135345200041.
It is an a-pointer prime, because the next prime (140002543559) can be obtained adding 140002543531 to its sum of digits (28).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 140002543531 - 27 = 140002543403 is a prime.
It is a super-2 number, since 2×1400025435312 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 140002543531.
It is not a weakly prime, because it can be changed into another prime (140002543501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70001271765 + 70001271766.
It is an arithmetic number, because the mean of its divisors is an integer number (70001271766).
Almost surely, 2140002543531 is an apocalyptic number.
140002543531 is a deficient number, since it is larger than the sum of its proper divisors (1).
140002543531 is an equidigital number, since it uses as much as digits as its factorization.
140002543531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 140002543531 its reverse (135345200041), we get a palindrome (275347743572).
The spelling of 140002543531 in words is "one hundred forty billion, two million, five hundred forty-three thousand, five hundred thirty-one".
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