140011343221333 has 2 divisors, whose sum is σ = 140011343221334. Its totient is φ = 140011343221332.

The previous prime is 140011343221291. The next prime is 140011343221363. The reversal of 140011343221333 is 333122343110041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 73343089427364 + 66668253793969 = 8564058^2 + 8165063^2 .

It is a cyclic number.

It is not a de Polignac number, because 140011343221333 - 2⁴⁵ = 104826971132501 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 140011343221295 and 140011343221304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140011343221363) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70005671610666 + 70005671610667.

It is an arithmetic number, because the mean of its divisors is an integer number (70005671610667).

Almost surely, 2^{140011343221333} is an apocalyptic number.

It is an amenable number.

140011343221333 is a deficient number, since it is larger than the sum of its proper divisors (1).

140011343221333 is an equidigital number, since it uses as much as digits as its factorization.

140011343221333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 140011343221333 its reverse (333122343110041), we get a palindrome (473133686331374).

The spelling of 140011343221333 in words is "one hundred forty trillion, eleven billion, three hundred forty-three million, two hundred twenty-one thousand, three hundred thirty-three".