Base | Representation |
---|---|
bin | 1100101110111110100010… |
… | …1100001110001010001111 |
3 | 1211120111112212022100101011 |
4 | 3023233220230032022033 |
5 | 3313343430243332421 |
6 | 45440021421030051 |
7 | 2643360563055502 |
oct | 313575054161217 |
9 | 54514485270334 |
10 | 14001202324111 |
11 | 4508970779582 |
12 | 16a163a3b5327 |
13 | 7a7400080232 |
14 | 36593a005139 |
15 | 19430b7474e1 |
hex | cbbe8b0e28f |
14001202324111 has 2 divisors, whose sum is σ = 14001202324112. Its totient is φ = 14001202324110.
The previous prime is 14001202324099. The next prime is 14001202324159. The reversal of 14001202324111 is 11142320210041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14001202324111 - 223 = 14001193935503 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14001202324181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7000601162055 + 7000601162056.
It is an arithmetic number, because the mean of its divisors is an integer number (7000601162056).
Almost surely, 214001202324111 is an apocalyptic number.
14001202324111 is a deficient number, since it is larger than the sum of its proper divisors (1).
14001202324111 is an equidigital number, since it uses as much as digits as its factorization.
14001202324111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 14001202324111 its reverse (11142320210041), we get a palindrome (25143522534152).
The spelling of 14001202324111 in words is "fourteen trillion, one billion, two hundred two million, three hundred twenty-four thousand, one hundred eleven".
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