140012023241113 has 2 divisors, whose sum is σ = 140012023241114. Its totient is φ = 140012023241112.

The previous prime is 140012023241089. The next prime is 140012023241191. The reversal of 140012023241113 is 311142320210041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 75372401065984 + 64639622175129 = 8681728^2 + 8039877^2 .

It is a cyclic number.

It is not a de Polignac number, because 140012023241113 - 2⁹ = 140012023240601 is a prime.

It is a super-2 number, since 2×140012023241113² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (140012023041113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70006011620556 + 70006011620557.

It is an arithmetic number, because the mean of its divisors is an integer number (70006011620557).

Almost surely, 2^{140012023241113} is an apocalyptic number.

It is an amenable number.

140012023241113 is a deficient number, since it is larger than the sum of its proper divisors (1).

140012023241113 is an equidigital number, since it uses as much as digits as its factorization.

140012023241113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 140012023241113 its reverse (311142320210041), we get a palindrome (451154343451154).

The spelling of 140012023241113 in words is "one hundred forty trillion, twelve billion, twenty-three million, two hundred forty-one thousand, one hundred thirteen".