Base | Representation |
---|---|
bin | 1100101110111110100010… |
… | …1100100001101111010111 |
3 | 1211120111112212110102101112 |
4 | 3023233220230201233113 |
5 | 3313343430303414221 |
6 | 45440021422445235 |
7 | 2643360563541353 |
oct | 313575054415727 |
9 | 54514485412345 |
10 | 14001202404311 |
11 | 4508970823861 |
12 | 16a163a43381b |
13 | 7a74000aa8a5 |
14 | 36593a026463 |
15 | 19430b76115b |
hex | cbbe8b21bd7 |
14001202404311 has 2 divisors, whose sum is σ = 14001202404312. Its totient is φ = 14001202404310.
The previous prime is 14001202404253. The next prime is 14001202404347. The reversal of 14001202404311 is 11340420210041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14001202404311 - 222 = 14001198210007 is a prime.
It is a super-2 number, since 2×140012024043112 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14001202404391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7000601202155 + 7000601202156.
It is an arithmetic number, because the mean of its divisors is an integer number (7000601202156).
Almost surely, 214001202404311 is an apocalyptic number.
14001202404311 is a deficient number, since it is larger than the sum of its proper divisors (1).
14001202404311 is an equidigital number, since it uses as much as digits as its factorization.
14001202404311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 14001202404311 its reverse (11340420210041), we get a palindrome (25341622614352).
The spelling of 14001202404311 in words is "fourteen trillion, one billion, two hundred two million, four hundred four thousand, three hundred eleven".
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