140012024412301 has 4 divisors (see below), whose sum is σ = 140014644402204. Its totient is φ = 140009404422400.

The previous prime is 140012024412277. The next prime is 140012024412343. The reversal of 140012024412301 is 103214420210041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 74943198836676 + 65068825575625 = 8656974^2 + 8066525^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140012024412301 is a prime.

It is a super-2 number, since 2×140012024412301² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140012024412361) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1309914790 + ... + 1310021671.

It is an arithmetic number, because the mean of its divisors is an integer number (35003661100551).

Almost surely, 2^{140012024412301} is an apocalyptic number.

It is an amenable number.

140012024412301 is a deficient number, since it is larger than the sum of its proper divisors (2619989903).

140012024412301 is an equidigital number, since it uses as much as digits as its factorization.

140012024412301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2619989902.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 140012024412301 its reverse (103214420210041), we get a palindrome (243226444622342).

The spelling of 140012024412301 in words is "one hundred forty trillion, twelve billion, twenty-four million, four hundred twelve thousand, three hundred one".