Base | Representation |
---|---|
bin | 11111110101011100010110… |
… | …111110101011100010110111 |
3 | 200100202000111201021222101111 |
4 | 133311130112332223202313 |
5 | 121322424111222143333 |
6 | 1213440345215535451 |
7 | 41330351326066606 |
oct | 3765342676534267 |
9 | 610660451258344 |
10 | 140012024412343 |
11 | 40680847747206 |
12 | 1385332782a587 |
13 | 6018100941aa5 |
14 | 2680892261a3d |
15 | 112c079e804cd |
hex | 7f5716fab8b7 |
140012024412343 has 2 divisors, whose sum is σ = 140012024412344. Its totient is φ = 140012024412342.
The previous prime is 140012024412277. The next prime is 140012024412361. The reversal of 140012024412343 is 343214420210041.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 140012024412343 - 225 = 140011990857911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140012024412643) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70006012206171 + 70006012206172.
It is an arithmetic number, because the mean of its divisors is an integer number (70006012206172).
Almost surely, 2140012024412343 is an apocalyptic number.
140012024412343 is a deficient number, since it is larger than the sum of its proper divisors (1).
140012024412343 is an equidigital number, since it uses as much as digits as its factorization.
140012024412343 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 140012024412343 its reverse (343214420210041), we get a palindrome (483226444622384).
The spelling of 140012024412343 in words is "one hundred forty trillion, twelve billion, twenty-four million, four hundred twelve thousand, three hundred forty-three".
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