14001230144032 has 12 divisors (see below), whose sum is σ = 27564921846126. Its totient is φ = 7000615072000.

The previous prime is 14001230144017. The next prime is 14001230144047. The reversal of 14001230144032 is 23044103210041.

It is an interprime number because it is at equal distance from previous prime (14001230144017) and next prime (14001230144047).

It can be written as a sum of positive squares in only one way, i.e., 13589574451216 + 411655692816 = 3686404^2 + 641604^2 .

It is a junction number, because it is equal to n+sod(n) for n = 14001230143988 and 14001230144006.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 218769220969 + ... + 218769221032.

Almost surely, 2^{14001230144032} is an apocalyptic number.

It is an amenable number.

14001230144032 is a deficient number, since it is larger than the sum of its proper divisors (13563691702094).

14001230144032 is an equidigital number, since it uses as much as digits as its factorization.

14001230144032 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 437538442011 (or 437538442003 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14001230144032 its reverse (23044103210041), we get a palindrome (37045333354073).

The spelling of 14001230144032 in words is "fourteen trillion, one billion, two hundred thirty million, one hundred forty-four thousand, thirty-two".