1400123113 has 2 divisors, whose sum is σ = 1400123114. Its totient is φ = 1400123112.

The previous prime is 1400123107. The next prime is 1400123119. The reversal of 1400123113 is 3113210041.

It is a balanced prime because it is at equal distance from previous prime (1400123107) and next prime (1400123119).

It can be written as a sum of positive squares in only one way, i.e., 713263849 + 686859264 = 26707^2 + 26208^2 .

It is an emirp because it is prime and its reverse (3113210041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1400123113 - 2²¹ = 1398025961 is a prime.

It is not a weakly prime, because it can be changed into another prime (1400123119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700061556 + 700061557.

It is an arithmetic number, because the mean of its divisors is an integer number (700061557).

Almost surely, 2^1400123113 is an apocalyptic number.

It is an amenable number.

1400123113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1400123113 is an equidigital number, since it uses as much as digits as its factorization.

1400123113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 1400123113 is about 37418.2189982367. The cubic root of 1400123113 is about 1118.7217328230.

Adding to 1400123113 its reverse (3113210041), we get a palindrome (4513333154).

The spelling of 1400123113 in words is "one billion, four hundred million, one hundred twenty-three thousand, one hundred thirteen".