Base | Representation |
---|---|
bin | 1000001001100101100… |
… | …0100110000100110011 |
3 | 111101101200212112122202 |
4 | 2002121120212010303 |
5 | 4243221123034211 |
6 | 144153141453415 |
7 | 13054431016616 |
oct | 2023130460463 |
9 | 441350775582 |
10 | 140012314931 |
11 | 54419335575 |
12 | 23175a1126b |
13 | 102842b4438 |
14 | 6ac311617d |
15 | 3996d5553b |
hex | 2099626133 |
140012314931 has 2 divisors, whose sum is σ = 140012314932. Its totient is φ = 140012314930.
The previous prime is 140012314927. The next prime is 140012314957. The reversal of 140012314931 is 139413210041.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 140012314931 - 22 = 140012314927 is a prime.
It is a super-2 number, since 2×1400123149312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 140012314894 and 140012314903.
It is not a weakly prime, because it can be changed into another prime (140012314991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70006157465 + 70006157466.
It is an arithmetic number, because the mean of its divisors is an integer number (70006157466).
Almost surely, 2140012314931 is an apocalyptic number.
140012314931 is a deficient number, since it is larger than the sum of its proper divisors (1).
140012314931 is an equidigital number, since it uses as much as digits as its factorization.
140012314931 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2592, while the sum is 29.
Adding to 140012314931 its reverse (139413210041), we get a palindrome (279425524972).
The spelling of 140012314931 in words is "one hundred forty billion, twelve million, three hundred fourteen thousand, nine hundred thirty-one".
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