Base | Representation |
---|---|
bin | 11111110101011101011111… |
… | …000010110001010010011111 |
3 | 200100202010121222022011000201 |
4 | 133311131133002301102133 |
5 | 121322434100230201444 |
6 | 1213441105205404331 |
7 | 41330423306512336 |
oct | 3765353702612237 |
9 | 610663558264021 |
10 | 140013233443999 |
11 | 40681308161623 |
12 | 138536047096a7 |
13 | 6018264279136 |
14 | 2680968a62d1d |
15 | 112c0eb1a1dd4 |
hex | 7f575f0b149f |
140013233443999 has 2 divisors, whose sum is σ = 140013233444000. Its totient is φ = 140013233443998.
The previous prime is 140013233443969. The next prime is 140013233444011. The reversal of 140013233443999 is 999344332310041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 140013233443999 - 211 = 140013233441951 is a prime.
It is a super-2 number, since 2×1400132334439992 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140013233443949) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70006616721999 + 70006616722000.
It is an arithmetic number, because the mean of its divisors is an integer number (70006616722000).
Almost surely, 2140013233443999 is an apocalyptic number.
140013233443999 is a deficient number, since it is larger than the sum of its proper divisors (1).
140013233443999 is an equidigital number, since it uses as much as digits as its factorization.
140013233443999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7558272, while the sum is 55.
The spelling of 140013233443999 in words is "one hundred forty trillion, thirteen billion, two hundred thirty-three million, four hundred forty-three thousand, nine hundred ninety-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •