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140013233443999 is a prime number
BaseRepresentation
bin11111110101011101011111…
…000010110001010010011111
3200100202010121222022011000201
4133311131133002301102133
5121322434100230201444
61213441105205404331
741330423306512336
oct3765353702612237
9610663558264021
10140013233443999
1140681308161623
12138536047096a7
136018264279136
142680968a62d1d
15112c0eb1a1dd4
hex7f575f0b149f

140013233443999 has 2 divisors, whose sum is σ = 140013233444000. Its totient is φ = 140013233443998.

The previous prime is 140013233443969. The next prime is 140013233444011. The reversal of 140013233443999 is 999344332310041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 140013233443999 - 211 = 140013233441951 is a prime.

It is a super-2 number, since 2×1400132334439992 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140013233443949) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70006616721999 + 70006616722000.

It is an arithmetic number, because the mean of its divisors is an integer number (70006616722000).

Almost surely, 2140013233443999 is an apocalyptic number.

140013233443999 is a deficient number, since it is larger than the sum of its proper divisors (1).

140013233443999 is an equidigital number, since it uses as much as digits as its factorization.

140013233443999 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7558272, while the sum is 55.

The spelling of 140013233443999 in words is "one hundred forty trillion, thirteen billion, two hundred thirty-three million, four hundred forty-three thousand, nine hundred ninety-nine".