140020213 has 2 divisors, whose sum is σ = 140020214. Its totient is φ = 140020212.

The previous prime is 140020171. The next prime is 140020219. The reversal of 140020213 is 312020041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 140019889 + 324 = 11833^2 + 18^2 .

It is an emirp because it is prime and its reverse (312020041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140020213 - 2¹³ = 140012021 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 140020193 and 140020202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140020219) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70010106 + 70010107.

It is an arithmetic number, because the mean of its divisors is an integer number (70010107).

Almost surely, 2^140020213 is an apocalyptic number.

It is an amenable number.

140020213 is a deficient number, since it is larger than the sum of its proper divisors (1).

140020213 is an equidigital number, since it uses as much as digits as its factorization.

140020213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 13.

The square root of 140020213 is about 11833.0136905186. The cubic root of 140020213 is about 519.2743984786.

Adding to 140020213 its reverse (312020041), we get a palindrome (452040254).

The spelling of 140020213 in words is "one hundred forty million, twenty thousand, two hundred thirteen".