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1400211000193 is a prime number
BaseRepresentation
bin10100011000000011000…
…101000100101110000001
311221212012010000201022211
4110120003011010232001
5140420113004001233
62551125325102121
7203106351060655
oct24300305045601
94855163021284
101400211000193
1149a90a673915
121a74539b7941
13a2068543065
144bab0652a65
152665193d5cd
hex14603144b81

1400211000193 has 2 divisors, whose sum is σ = 1400211000194. Its totient is φ = 1400211000192.

The previous prime is 1400211000191. The next prime is 1400211000259. The reversal of 1400211000193 is 3910001120041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1033451161744 + 366759838449 = 1016588^2 + 605607^2 .

It is a cyclic number.

It is not a de Polignac number, because 1400211000193 - 21 = 1400211000191 is a prime.

It is a super-2 number, since 2×14002110001932 (a number of 25 digits) contains 22 as substring.

Together with 1400211000191, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1400211000191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700105500096 + 700105500097.

It is an arithmetic number, because the mean of its divisors is an integer number (700105500097).

Almost surely, 21400211000193 is an apocalyptic number.

It is an amenable number.

1400211000193 is a deficient number, since it is larger than the sum of its proper divisors (1).

1400211000193 is an equidigital number, since it uses as much as digits as its factorization.

1400211000193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 22.

The spelling of 1400211000193 in words is "one trillion, four hundred billion, two hundred eleven million, one hundred ninety-three", and thus it is an aban number.