Base | Representation |
---|---|
bin | 1100101111000001111011… |
… | …0111000011011010001011 |
3 | 1211120120220012101122020121 |
4 | 3023300132313003122023 |
5 | 3313402310422231243 |
6 | 45440251524004111 |
7 | 2643422236604155 |
oct | 313603667033213 |
9 | 54516805348217 |
10 | 14002111133323 |
11 | 4509297778375 |
12 | 16a1852830637 |
13 | 7a751643c471 |
14 | 3659c49b5ad5 |
15 | 1943614141ed |
hex | cbc1edc368b |
14002111133323 has 2 divisors, whose sum is σ = 14002111133324. Its totient is φ = 14002111133322.
The previous prime is 14002111133303. The next prime is 14002111133327. The reversal of 14002111133323 is 32333111120041.
It is a strong prime.
It is an emirp because it is prime and its reverse (32333111120041) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14002111133323 is a prime.
It is not a weakly prime, because it can be changed into another prime (14002111133327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7001055566661 + 7001055566662.
It is an arithmetic number, because the mean of its divisors is an integer number (7001055566662).
Almost surely, 214002111133323 is an apocalyptic number.
14002111133323 is a deficient number, since it is larger than the sum of its proper divisors (1).
14002111133323 is an equidigital number, since it uses as much as digits as its factorization.
14002111133323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 14002111133323 its reverse (32333111120041), we get a palindrome (46335222253364).
The spelling of 14002111133323 in words is "fourteen trillion, two billion, one hundred eleven million, one hundred thirty-three thousand, three hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •