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14002324153 is a prime number
BaseRepresentation
bin11010000101001101…
…01000001010111001
31100010211211202201021
431002212220022321
5212134043333103
610233234222441
71003663535326
oct150246501271
940124752637
1014002324153
115a35a46424
122869424a21
131421c43a0c
1496b91db4d
1556e441bbd
hex3429a82b9

14002324153 has 2 divisors, whose sum is σ = 14002324154. Its totient is φ = 14002324152.

The previous prime is 14002324103. The next prime is 14002324157. The reversal of 14002324153 is 35142320041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8444323449 + 5558000704 = 91893^2 + 74552^2 .

It is an emirp because it is prime and its reverse (35142320041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14002324153 - 213 = 14002315961 is a prime.

It is not a weakly prime, because it can be changed into another prime (14002324157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7001162076 + 7001162077.

It is an arithmetic number, because the mean of its divisors is an integer number (7001162077).

Almost surely, 214002324153 is an apocalyptic number.

It is an amenable number.

14002324153 is a deficient number, since it is larger than the sum of its proper divisors (1).

14002324153 is an equidigital number, since it uses as much as digits as its factorization.

14002324153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 14002324153 its reverse (35142320041), we get a palindrome (49144644194).

The spelling of 14002324153 in words is "fourteen billion, two million, three hundred twenty-four thousand, one hundred fifty-three".